由 lcflcflcf 於 星期三 十二月 22, 2004 10:58 am
1+x+y+xy=15
x+y+xy=14
First, let x be the bigger one
if
y=1, the max num of x is 6
y=2, the max num of x is 4
y cannot be 3, 4, 5 and so on.
So
y=1 or 2
if y=1, x=6,1+6+1*6=13
y cannot be 1
So
y=2
x+2+2x=14
x+2x=12
3x=12
x=4
so x=4, y=2
This is my notion, i sure that there are some solutions which can be firster.
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