由 galaxylee 於 星期一 二月 27, 2006 9:26 pm
#ed_op#DIV#ed_cl#1-1/2+1/3-1/4+...-1/1318+1/1319#ed_op#BR#ed_cl#=1+1/2+1/3+...+1/1319-2(1/2+1/4+...+1/1318)#ed_op#BR#ed_cl#=1+1/2+1/3+...+1/1319-1-1/2-1/3-...-1/659#ed_op#BR#ed_cl#=1/660+1/661+...+1/1319#ed_op#BR#ed_cl#=1/(659+1)+1/(659+2)+...+1/(659+330)+1/(1320-330)+1/(1320-329)+...+1/(1320-1)#ed_op#BR#ed_cl#=[1/(659+1)+1/(1320-1)]+...+[1/(659+330)+1/(1320-330)]#ed_op#BR#ed_cl#=1979/(660*1319)+1979/(661*1318)+...+1979/(989*990)#ed_op#BR#ed_cl#=1979*[1/(660*1319)+1/(661*1318)+...+1/(989*990)]#ed_op#BR#ed_cl#=(1979*k)/(660*661*...*1319)#ed_op#BR#ed_cl#=q/p,其中k是自然數#ed_op#BR#ed_cl#1979是質數,和660,661,...,1319無1以外的公因數#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#所以q是1979的倍數#ed_op#/DIV#ed_cl#