Anonymous 寫到:請打救：
A is an invertible square matrix, A’A = AA’ = I, A’ is the transpose of A.
B =A^(-1)A’, A^(-1) is the inverse of A, det A is not equal to det B.
Show det(A+B)=0.
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Re: [大學]Matrix
由 lskuo 於 星期五 六月 25, 2021 6:05 pm
[大學]Matrix
由 訪客 於 星期五 六月 25, 2021 3:01 pm
請打救：
A is an invertible square matrix, A’A = AA’ = I, A’ is the transpose of A.
B =A^(-1)A’, A^(-1) is the inverse of A, det A is not equal to det B.
Show det(A+B)=0.
A is an invertible square matrix, A’A = AA’ = I, A’ is the transpose of A.
B =A^(-1)A’, A^(-1) is the inverse of A, det A is not equal to det B.
Show det(A+B)=0.