YLL討論網

由 **G@ry** 於星期二六月 12, 2007 6:57 pm

這是external OR 的問題：#ed_op#br#ed_cl#設數列長度為x，#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕=#ed_op#/span#ed_cl#External OR；#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#，n>0，解為將所有數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕：#ed_op#/span#ed_cl##ed_op#br#ed_cl#e.g. 10001001111010110100101101001111, x=2#ed_op#sup#ed_cl#5#ed_op#/sup#ed_cl#, 有18個1 => 0;#ed_op#br#ed_cl#e.g. 1001010010011100, x=2#ed_op#sup#ed_cl#4#ed_op#/sup#ed_cl#, 有7個1=> 1;#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#+1，n>0，解為將首尾數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕#ed_op#/span#ed_cl#：#ed_op#br#ed_cl#e.g. 11110001101110100000111101010010100111010000010011000010110111011 = 0;#ed_op#br#ed_cl#e.g. 101100000001101111110111111100100 = 1;#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#-1，n>0，解為將單位數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕#ed_op#/span#ed_cl#：#ed_op#br#ed_cl#e.g. 1111100001111000010010111001101, 單位有10個1 => 0;#ed_op#br#ed_cl#e.g. 110100110111010, 單位有3個1 => 1;#ed_op#br#ed_cl#暫時只想到x=2次方的通解，未想到x=所有正整數的通解...#ed_op#br#ed_cl#還在思考中...#ed_op#br#ed_cl##ed_op#br#ed_cl#對於最後k個數字，跟預測最後一個數字一樣，將x-k當成x來計，作k次運算便可以了....#ed_op#br#ed_cl##ed_op#br#ed_cl#

由 **guevara4900** 於星期一六月 11, 2007 11:43 pm

這樣也不對啊!
如
010101010101
11111111111
0000000000
000000000
00000000
0000000
000000
00000
0000
000
00
0
結論是0

由 **急需答案** 於星期一六月 11, 2007 11:32 pm

我其實也不太清楚題目的意思
但是我想應該是這樣吧!!!
001110
01001
  1101
   011
    10
     1

所以結論是1

由 **guevara4900** 於星期一六月 11, 2007 11:16 pm

你的描述有點不太懂,可以舉例一下嗎?

由 **急需答案** 於星期一六月 11, 2007 7:27 pm

#ed_op#DIV#ed_cl#隨便寫下一個0和1的排列，假如連續兩個相同的話，#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#在他們下面寫一個0，假如不同的話，寫下一個1。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#重複這個過程直到你只剩下一個阿拉伯數字。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#你能預測最後一個數字是什麼嗎???#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#最後K個數字呢???#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#真的很急#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#希望知道答案的大大能給個答案!!!#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#拜託~~~#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#

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[邏輯]0與1的排列

[邏輯]0與1的排列

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[quote="G@ry"]這是external OR 的問題：#ed_op#br#ed_cl#設數列長度為x，#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕=#ed_op#/span#ed_cl#External OR；#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#，n>0，解為將所有數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕：#ed_op#/span#ed_cl##ed_op#br#ed_cl#e.g. 10001001111010110100101101001111, x=2#ed_op#sup#ed_cl#5#ed_op#/sup#ed_cl#, 有18個1 => 0;#ed_op#br#ed_cl#e.g. 1001010010011100, x=2#ed_op#sup#ed_cl#4#ed_op#/sup#ed_cl#, 有7個1=> 1;#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#+1，n>0，解為將首尾數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕#ed_op#/span#ed_cl#：#ed_op#br#ed_cl#e.g. 11110001101110100000111101010010100111010000010011000010110111011 = 0;#ed_op#br#ed_cl#e.g. 101100000001101111110111111100100 = 1;#ed_op#br#ed_cl#當x=2#ed_op#sup#ed_cl#n#ed_op#/sup#ed_cl#-1，n>0，解為將單位數字#ed_op#span style="font-size: 12pt; font-family: 新細明體;"#ed_cl#⊕#ed_op#/span#ed_cl#：#ed_op#br#ed_cl#e.g. 1111100001111000010010111001101, 單位有10個1 => 0;#ed_op#br#ed_cl#e.g. 110100110111010, 單位有3個1 => 1;#ed_op#br#ed_cl#暫時只想到x=2次方的通解，未想到x=所有正整數的通解...#ed_op#br#ed_cl#還在思考中...#ed_op#br#ed_cl##ed_op#br#ed_cl#對於最後k個數字，跟預測最後一個數字一樣，將x-k當成x來計，作k次運算便可以了....#ed_op#br#ed_cl##ed_op#br#ed_cl# [/quote]