#ed_op#DIV#ed_cl#考慮到負數,可以再乘以8#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#共有7*6*8組#ed_op#/DIV#ed_cl#aaddfg 寫到:目前只知道3022不是四的倍數#ed_op#BR#ed_cl#XYZ中必有兩奇數....#ed_op#BR#ed_cl#算法在看看#ed_op#BR#ed_cl##ed_op#BR#ed_cl#用EXCEL找出來的有7*6組#ed_op#BR#ed_cl#(54,9,5)(50,21,9)(42,33,13)(42,27,23)(30,41,21)(14,51,15)(6,45,31)