[數學]三角代數
由 n111111111 於 星期四 二月 01, 2007 12:18 am
#ed_op#DIV#ed_cl#x + y = tanθ + cotθ#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#x#ed_op#SUP#ed_cl#2 #ed_op#/SUP#ed_cl#+ y#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl# = 1 + sin2θ#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#則 x = ? , y = ?#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#