#ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#這題沒有順序之分且要考慮正負#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl#shinz_lai 寫到:#ed_op#P#ed_cl#四個整數若有順序之分的話,這樣的整數解個數為:#ed_op#/P#ed_cl##ed_op#P#ed_cl#(4^4-3^4)(3^4-2^4)(3^4-2^4)*16=11830000組 #ed_op#/P#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#