ABC is an isosceles triangle with a vertical angle of 20 , a point D is
marked off on AC such that AD = BC. Find angle ABD.
[數學]geometry
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[數學]geometry
由 Alexxx 於 星期五 八月 01, 2003 11:58 pm
ABC is an isosceles triangle with a vertical angle of 20 , a point D is
marked off on AC such that AD = BC. Find angle ABD.
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Alexxx - 訪客
由 Raceleader 於 星期六 八月 02, 2003 12:00 am
You can get what you want from:
http://yll.loxa.edu.tw/phpBB2/viewtopic.php?t=582
http://yll.loxa.edu.tw/phpBB2/viewtopic.php?t=582
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Raceleader - 訪客
由 Raceleader 於 星期六 八月 02, 2003 12:09 am
BCE is an equilateral triangle. Join AE
EB=DA, ∠DAB=∠EBA=20°, AB as a common sides
Then you prove that △AEB≡△BDA
∠ABD=∠EAB=10°
EB=DA, ∠DAB=∠EBA=20°, AB as a common sides
Then you prove that △AEB≡△BDA
∠ABD=∠EAB=10°
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Raceleader - 訪客
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