[數學]正4面體

[數學]正4面體

yll 於 星期四 四月 10, 2003 8:38 am


正4面體
邊長1
求體積 ㄏㄏㄏ
分享我的教學和生活,複雜的事情簡單做!
帥哥良&小帥 Youtube

yll
帥哥良~
帥哥良~
 
文章: 4382
註冊時間: 2002-08-28
來自: 我將來要去的地方~

Raceleader 於 星期四 四月 10, 2003 8:59 am


Let O be the Centroid of base triangle ABC, the apex is D:

We can draw AO to cut BC at E
By congruent triangle, we get that ∠AEB=∠ AEC=90°
By Pythagoras, we get AE=√3/2

Since O is the centroid, so AO:OE=2:1
So, OA=√3/3

We get that base area = (1/2)(AE)(BC) = √3/4

By Pythagoras Theorem:
DO2+OA2=AD2
DO2+1/3=1
DO= √(2/3)

So, the volume = (1/3)(Base area)(height)=√2/12

Raceleader
訪客
 




平面&空間幾何