(a3-b3)/3+ab2
=(a-b)3/3+a2b-ab2+ab2
=(a-b)3/3+a2b >a2b
√22=2<2.25=9/4
√2<3/2
+ / -檢視主題
[大學]0.0
由 tree465 於 星期二 十一月 17, 2009 8:14 pm
[數學]幫忙解題吧~
由 訪客 於 星期二 十月 13, 2009 11:06 pm
In an ordered field if a>b show that a²b<ab²+(a³-b³)/3
prove thaat in an ordered field.
if √2 is a positive number whose square is 2,then √2 <3/2
proposition Let a≤x≤b ∀n and Xn→X Then a≤x≤b
proof (1) claim:x≤b
(2) claim:x≥a
prove thaat in an ordered field.
if √2 is a positive number whose square is 2,then √2 <3/2
proposition Let a≤x≤b ∀n and Xn→X Then a≤x≤b
proof (1) claim:x≤b
(2) claim:x≥a