YLL討論網

#ed_op#DIV#ed_cl##ed_op#DIV class=news_detail#ed_cl##ed_op#P#ed_cl##ed_op#STRONG#ed_cl##ed_op#FONT color=#c00000#ed_cl#來源：#ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl##ed_op#A href="http://popblog.tvbs.com.tw/blog/puzzles/"#ed_cl#http://popblog.tvbs.com.tw/blog/puzzles/#ed_op#/A#ed_cl##ed_op#/P#ed_cl##ed_op#P#ed_cl#第一個解開這款#ed_op#STRONG#ed_cl##ed_op#FONT color=#40a0ff#ed_cl#拼圖遊戲#ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl#的人就可以得到#ed_op#STRONG#ed_cl##ed_op#FONT color=#c00000#ed_cl#100萬英鎊#ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl##ed_op#IMG src="http://yll.loxa.edu.tw/phpBB2/richedit/smileys//yy23.gif"#ed_cl##ed_op#/P#ed_cl##ed_op#P#ed_cl##ed_op#IMG alt="image file name: 2kbbd2f361bc.jpg" src="http://yll.loxa.edu.tw/phpBB2/richedit/upload/2kbbd2f361bc.jpg" border=0#ed_cl##ed_op#/P#ed_cl##ed_op#P#ed_cl##ed_op#STRONG#ed_cl##ed_op#FONT color=#007f40#ed_cl#遊戲名稱: EternityII#ed_op#BR#ed_cl#遊戲發行時間: 2007 年7 月28 日#ed_op#BR#ed_cl#消息來源: #ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl##ed_op#A href="http://www.puzzles.com/PuzzleClub/CoolNewsHome.htm#EternityII"#ed_cl##ed_op#STRONG#ed_cl##ed_op#FONT color=#007f40#ed_cl#Puzzle Club#ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl##ed_op#/A#ed_cl##ed_op#/P#ed_cl##ed_op#P#ed_cl#1999年發行了拼圖遊戲 Eternity, #ed_op#STRONG#ed_cl##ed_op#FONT color=#40a0ff#ed_cl#過了18個月才有兩個數學家用程式解出拼法#ed_op#/FONT#ed_cl##ed_op#/STRONG#ed_cl#。這次號稱更難, 賞金也更高。#ed_op#/P#ed_cl##ed_op#P#ed_cl#有興趣的話去到以下幾個網站去看看, 祝你們拿到那100萬英鎊#ed_op#/P#ed_cl##ed_op#P#ed_cl##ed_op#A href="http://www.eternityii.com/"#ed_cl#EternityII#ed_op#/A#ed_cl##ed_op#BR#ed_cl##ed_op#A href="http://news.bbc.co.uk/2/hi/uk_news/scotland/tayside_and_central/6295279.stm"#ed_cl#BBC News 的介紹#ed_op#/A#ed_cl##ed_op#BR#ed_cl##ed_op#A href="http://news.bbc.co.uk/1/hi/uk/953316.stm"#ed_cl#BBC News 對 Eternity 的報導#ed_op#/A#ed_cl##ed_op#BR#ed_cl##ed_op#A href="http://www.archduke.demon.co.uk/eternity/"#ed_cl#Eternity 的解答#ed_op#/A#ed_cl##ed_op#BR#ed_cl##ed_op#A href="http://jjjasont.spaces.live.com/blog/cns!390016FEA82F7FA2!218.entry#post"#ed_cl#國內一篇 Blog 對 Eternity I 及 II 的介紹#ed_op#/A#ed_cl##ed_op#/P#ed_cl##ed_op#/DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#