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[問題]有誰會行列式餘因子展開的證明呢!
由 相遇即是有緣 於 星期四 十一月 23, 2006 11:27 pm
#ed_op#DIV#ed_cl##ed_op#P#ed_cl#設一個 n by n 矩陣 A#ed_op#/P#ed_cl##ed_op#P#ed_cl#則 |A| = Σ#ed_op#SUB#ed_cl#j=1#ed_op#/SUB#ed_cl##ed_op#SUP#ed_cl#n#ed_op#/SUP#ed_cl#〔a#ed_op#SUB#ed_cl#ij #ed_op#/SUB#ed_cl#* (-1)#ed_op#SUP#ed_cl#i+j #ed_op#/SUP#ed_cl#* M#ed_op#SUB#ed_cl#ij#ed_op#/SUB#ed_cl#〕#ed_op#SUB#ed_cl# ,#ed_op#/SUB#ed_cl#(1≦ i ≦n)#ed_op#/P#ed_cl##ed_op#P#ed_cl#以上為行列式 |A| 由某一列展開的結果,請問這個要怎麼證明呢!?#ed_op#/P#ed_cl##ed_op#/DIV#ed_cl#