由 jackhoung 於 星期四 七月 27, 2006 5:30 pm
#ed_op#DIV#ed_cl#連接O2A,O1O2,O1B#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#則#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#O1A=√[(R+r)^2-r^2]=√(R^2+2Rr)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#AB=√(O1A^2-R^2)=√(R^2+2Rr-r^2)=√2Rr#ed_op#/DIV#ed_cl#