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發表 jackhoung 於 星期一 五月 29, 2006 8:59 am

#ed_op#DIV#ed_cl##ed_op#P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"#ed_cl##ed_op#SPAN style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: 新細明體; mso-ascii-font-family: Verdana; mso-hansi-font-family: Verdana"#ed_cl#作#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: Verdana"#ed_cl#AH#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: 新細明體; mso-ascii-font-family: Verdana; mso-hansi-font-family: Verdana"#ed_cl#垂直#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: Verdana"#ed_cl#BC#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: 新細明體; mso-ascii-font-family: Verdana; mso-hansi-font-family: Verdana"#ed_cl#於#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-SIZE: 14pt; COLOR: black; FONT-FAMILY: Verdana"#ed_cl#H#ed_op#?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /#ed_cl##ed_op#o:p#ed_cl##ed_op#/o:p#ed_cl##ed_op#/SPAN#ed_cl##ed_op#/P#ed_cl##ed_op#P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"#ed_cl##ed_op#SPAN style="FONT-SIZE: 14pt; 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發表 SDFDFGGH 於 星期一 五月 29, 2006 12:54 am

#ed_op#DIV#ed_cl#上面好像有點矛盾#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#

發表 宇智波鼬 於 星期日 五月 28, 2006 6:59 pm

我這裡將詳細方法講一下:

作E在DC上使得BE=BC 作F在AC上使得EF=BE. 作G在AB上使得EF=FG

所以角BEC=角BCE=80度 角EBF=EFB=60度.
角FEG=角FGE=40度 角GFA=20度=角GAF
所以 AG=GF=FE=EB=BC 所以 G等於D.
而且BEF是正三角形 所以FG=FB
角GFB=160度 角GBF=10度 所以DBC=70度.

發表 aa2191943 於 星期日 五月 28, 2006 5:40 pm

#ed_op#DIV#ed_cl#作AH垂直BC,H在BD上#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#在證AH=BH,得角DBC=70度#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#(註:20-80-80的三角形也很特別,常被出成考題)#ed_op#/DIV#ed_cl#

[數學]幾何題..(66)

發表 ☆ ~ 幻 星 ~ ☆ 於 星期日 五月 28, 2006 5:09 pm

左鍵: 點擊縮放; 右鍵: 觀看原圖

如圖,△ABC為一等腰三角形,AB=AC,∠A=20°,D為AC上一點,且AD=BC,試求∠DBC