由 亂解一通 於 星期二 四月 11, 2006 11:44 pm
#ed_op#DIV#ed_cl#建議你先把書看懂,然後再解題。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#其實每題都不算很難,都算是很基本的題目。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#此題部分:#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#函數極限有一個重要的性質,左極限等於右極限也等於極限值,所以只需#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#檢驗是否由左邊過來與右邊過來帶該點數值是否相同就可以簡單判定。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#至於連續則是比極限條件要強一點,要保證該點函數值要等於極限值#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#本題一開始就無極限了,自然就不需討論連續了!#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#對單變元函數而言,可微 <=> 可導 => 連續 => 極限存在#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#解答: ?的地方是我看不懂的,不過不影響結果。#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#P align=left#ed_cl##ed_op#IMG style="WIDTH: 347px; HEIGHT: 151px" height=151 alt="image file name: 2k390a91d849.png" src="http://yll.loxa.edu.tw/phpBB2/richedit/upload/2k390a91d849.png" width=375 border=0#ed_cl##ed_op#/P#ed_cl##ed_op#P align=center#ed_cl##ed_op#B#ed_cl##ed_op#FONT face=Verdana size=2#ed_cl##ed_op#/FONT#ed_cl##ed_op#/B#ed_cl# #ed_op#/P#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#