#ed_op#DIV#ed_cl#----------------------------------#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#謝了#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#其實今天也終於看懂#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2年沒碰數學複習起來真痛苦#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#當兵真是害人#ed_op#/DIV#ed_cl#Anonymous 寫到:#ed_op#DIV#ed_cl#1. L{f''(t)} = s#ed_op#SUP#ed_cl#2 #ed_op#SUB#ed_cl#*#ed_op#/SUB#ed_cl##ed_op#/SUP#ed_cl# L{f(t)} - s f(0) -f'(0)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2. Let g(t) =34t then L{g(t)}=34/s#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl##ed_op#/DIV#ed_cl#
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由 taco7103 於 星期六 三月 18, 2006 8:13 pm
由 訪客 於 星期六 三月 18, 2006 6:57 pm
#ed_op#DIV#ed_cl#1. L{f''(t)} = s#ed_op#SUP#ed_cl#2 #ed_op#SUB#ed_cl#*#ed_op#/SUB#ed_cl##ed_op#/SUP#ed_cl# L{f(t)} - s f(0) -f'(0)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2. Let g(t) =34t then L{g(t)}=34/s#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl##ed_op#/DIV#ed_cl#
[數學]幫我解解"拉式"問題(我被他拉倒了)
由 taco7103 於 星期五 三月 17, 2006 8:46 pm
#ed_op#DIV#ed_cl##ed_op#SPAN lang=EN-US style="FONT-SIZE: 9pt; COLOR: blue; FONT-FAMILY: Arial"#ed_cl##ed_op#FONT face=Verdana color=#000000#ed_cl#因為當完兵….有些東西頭在看已經忘了-----------(要考研究所#ed_op#BR#ed_cl#要複習)#ed_op#BR#ed_cl##ed_op#BR#ed_cl#題目：y”+4y=sinx y(0)=1 , y’(0)=0#ed_op#BR#ed_cl#轉拉式#ed_op#BR#ed_cl#-------(s^2+4)L[y]=s+1/(s^2+1)------#ed_op#BR#ed_cl#問題來了= =#ed_op#BR#ed_cl#我是知道sinx轉拉式是1/(s^2+1) ,可是在條件多了 y(0)#ed_op#BR#ed_cl#=1 , y’(0)=0 為何會多了一個 s#ed_op#BR#ed_cl##ed_op#BR#ed_cl#一個人看講義題目真的搞不懂 ,轉出來後面是會算 ,但前面怎轉#ed_op#BR#ed_cl#出來是一大頭痛.#ed_op#BR#ed_cl#這提也差不多Orz#ed_op#BR#ed_cl#1/4y”+y’+17y=34t 條件 y(0)=0 ,y’(0)=-2 多出後面#ed_op#BR#ed_cl#的T我就搞不懂怎麼算 ,2年沒算了= =#ed_op#BR#ed_cl##ed_op#BR#ed_cl#拜託知道的大大博士(老師) ,能幫忙解釋麼??謝謝您的指導!!!#ed_op#BR#ed_cl##ed_op#BR#ed_cl#我的E-MAIL：taco7103@yahoo.com.tw#ed_op#BR#ed_cl#再次謝謝您!!!#ed_op#BR#ed_cl#能多次幫忙的請PO一下E-MAIL有問題能再次請教您(希望”熱力#ed_op#BR#ed_cl#學”也能多幫忙----因要報考熱流組Orz…………)#ed_op#/FONT#ed_cl##ed_op#BR#ed_cl##ed_op#/SPAN#ed_cl##ed_op#/DIV#ed_cl#