由 訪客 於 星期日 二月 26, 2006 2:26 pm
#ed_op#DIV#ed_cl#f(x) = (sinx)/x for x in (0,1)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#令#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#F(x)=1 for x=0 #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#F(x)=(sinx)/x for x in (0,1)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#F(x)=sinx1 for x=1#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#則#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#F(x) 在[0,1]為連續函數,所以F(x)在[0,1]為可積#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#所以 F(x)在(0,1)亦為可知#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#所以f(x)在(0,1)可積#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#其實這題改為 在正實數可積比較有趣#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#