#ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#二連敗:3種........... ↓↓0↓↓0↓↓0.......〈任取一對↓〉#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#這樣比較容易明白#ed_op#/DIV#ed_cl#娜可兒 寫到:#ed_op#BR#ed_cl#二負的情況有誤,應為6種,而非3種#ed_op#BR#ed_cl#(因為你沒考慮到連敗的情形)#ed_op#BR#ed_cl#二負的情況:分開敗:3種........... ↓0↓0↓0.......〈任取兩個↓〉#ed_op#BR#ed_cl# 二連敗:3種........... ↓0↓0↓0.......〈任取一個↓〉gndagnda 寫到:不知是否如此:只有兩種情形,要嘛A勝,要嘛B勝,個有以下的情形:#ed_op#BR#ed_cl#A勝:1.三連勝:1種#ed_op#BR#ed_cl#2.一負:3種........... ↓0↓0↓0.......〈↓代表負局可以在哪裡產生〉#ed_op#BR#ed_cl#3.二負:3種............ ↓0↓0↓0.......〈任取兩個↓〉#ed_op#BR#ed_cl#B勝:情形與A相同#ed_op#BR#ed_cl##ed_op#BR#ed_cl#所以共14種