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發表 destinysky19 於 星期三 一月 27, 2010 11:11 pm

啊...不好意思...
看懂了...
其實我問的原因是...
我剛開到這題時想看題目怎麼解...
可是我又剛好在忙~
所以就複製下來放到TXT文字紋建檔裡面看~
但是-號不知道為什麼沒有出現~
所以我才看不懂...
抱歉了...
有點冒失...

發表 destinysky19 於 星期三 一月 27, 2010 11:09 pm

aa2191943 寫到:#ed_op#DIV#ed_cl#我來舉一個例題:#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#問:化簡#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5) + #ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#解:令x=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5) + #ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#         a=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)     b=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#     所以x#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#=[#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)]#ed_op#SUP#ed_cl#3 #ed_op#/SUP#ed_cl#+ [#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)]#ed_op#SUP#ed_cl#3 #ed_op#/SUP#ed_cl#+3ab(a+b)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                =(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)+(2+√5)+3abx#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                =4+3(-1)x#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#     所以x#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#+3x-4=0#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                 解得x=1#ed_op#/DIV#ed_cl#

請問...
由(2√5)+(2+√5)+3abx話減為4+3(-1)x可以慢一點麼...?
有點看不太懂...多謝囉~

發表 aa2191943 於 星期三 五月 31, 2006 11:03 am

#ed_op#DIV#ed_cl#我來舉一個例題:#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#問:化簡#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5) + #ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#解:令x=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5) + #ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#         a=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)     b=#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#     所以x#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#=[#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)]#ed_op#SUP#ed_cl#3 #ed_op#/SUP#ed_cl#+ [#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#√(2+√5)]#ed_op#SUP#ed_cl#3 #ed_op#/SUP#ed_cl#+3ab(a+b)#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                =(2#ed_op#STRIKE#ed_cl#  #ed_op#/STRIKE#ed_cl#√5)+(2+√5)+3abx#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                =4+3(-1)x#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#     所以x#ed_op#SUP#ed_cl#3#ed_op#/SUP#ed_cl#+3x-4=0#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#                 解得x=1#ed_op#/DIV#ed_cl#

發表 6213 於 星期三 三月 29, 2006 2:02 pm

#ed_op#DIV#ed_cl#2*3=6#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#開6次吧!#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#〈沒記錯是這樣〉#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#不知有無誤解你的意思?#ed_op#/DIV#ed_cl#

[問題]開3次雙重根號

發表 浩浩 於 星期二 四月 27, 2004 7:24 pm

2次的雙重根號只要把裡頭配成完全平方式就行了.
而3次的雙重根號也是要如法炮製,把裡頭配成完全立方嗎?
而如果說,在一個3次根號裡有跟2次根號,那又得如何開呢?