e^(i*A)=cosA+isinA
要找1^i
令e^A=1
=>A=0
1^i=e^(i*0)=cos0+isin0=1
應該是這樣吧
耀耀 寫到:阿...
我有一個問題耶...
ipi是什麼阿?
(沒學過~來學一學~)
謝謝囉~ (偶還是小6)
FBInstant 寫到:0^0
let f(x)=x^x
when x->0
lim x->0 x^x
=e^(lim x->0 xlnx)
=e^(lim x->0 lnx/(1/x))
=e^(limx->0 (1/x)/[-(1/x)^2] by hospital's rule
=e^limx->0 -x
=e^0
=1
Raceleader 寫到:x->0+
Not x->0
Raceleader 寫到:FBInstant: Your proof has problem