#ed_op#br#ed_cl#(1) 重疊區ABC面積 = arcBC x 3 - △ABC x 2 = AB半徑之半圓 - △ABC x 2#ed_op#br#ed_cl#= #ed_op#sub#ed_cl##ed_op#img src="http://yll.loxa.edu.tw/phpBB2/richedit/buttons/symbol.gif"#ed_cl##ed_op#/sub#ed_cl#(AB)#ed_op#sup#ed_cl#2#ed_op#/sup#ed_cl# - 2 x √3(AB)#ed_op#sup#ed_cl#2#ed_op#/sup#ed_cl#/4 = (#ed_op#sub#ed_cl##ed_op#img src="richedit/buttons/symbol.gif"#ed_cl##ed_op#/sub#ed_cl#-√3/2)(AB)#ed_op#sup#ed_cl#2#ed_op#/sup#ed_cl##ed_op#br#ed_cl##ed_op#br#ed_cl#(2) 待續...#ed_op#br#ed_cl##ed_op#br#ed_cl#mythman3200 寫到:#ed_op#div#ed_cl##ed_op#img src="http://www.mathland.idv.tw/solution/890701.gif" border="0" height="145" width="173"#ed_cl##ed_op#/div#ed_cl##ed_op#div#ed_cl# #ed_op#/div#ed_cl##ed_op#div#ed_cl##ed_op#font size="2"#ed_cl##ed_op#/font#ed_cl# #ed_op#/div#ed_cl##ed_op#div#ed_cl##ed_op#font size="2"#ed_cl#(1)分別以三個頂點為圓心，AB為半徑作 #ed_op#span style="letter-spacing: 1px;"#ed_cl##ed_op#font color="#000000" size="2"#ed_cl#圓，求其重疊區域ABC的面積?#ed_op#/font#ed_cl##ed_op#/span#ed_cl##ed_op#/font#ed_cl##ed_op#/div#ed_cl##ed_op#div#ed_cl##ed_op#font size="2"#ed_cl#(2)分別以三個頂點為圓心，△ABC的高為半徑作圓，求其重疊區域DEF的面積?#ed_op#/font#ed_cl##ed_op#br#ed_cl##ed_op#br#ed_cl##ed_op#/div#ed_cl##ed_op#div#ed_cl##ed_op#/div#ed_cl#
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Re: [數學]面積問題
由 G@ry 於 星期二 十一月 20, 2007 2:48 am
[測試]f;f
由 mythman3200 於 星期一 十一月 19, 2007 9:49 pm
lol