[數學]幾何題.
由 skywalker 於 星期六 十二月 23, 2006 11:13 am
#ed_op#DIV#ed_cl#直角三角形ABC中,D是斜AB上任一點,求證#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#(CD*AB)#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl#=(AD*BC)#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl#+(BD*AC)#ed_op#SUP#ed_cl#2#ed_op#/SUP#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#