等待著的深藍 寫到:#ed_op#DIV#ed_cl#1.證明對於大於3的任意質數P,皆可表示成6n+1或6n-1的形式,且n∈N#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2.找出所有的質數P使得P+3亦為質數#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#3.證明:是否有無限多個質數P使得P+2亦為質數,若非無限多個,請找出P的最大值#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl##ed_op#P#ed_cl#
#ed_op#/P#ed_cl##ed_op#P#ed_cl#1.一數一定為6n+1,6n+2,6n+3,6n-2,6n-1任一種(n>=1),但6n+2,6n+3,6n-2皆為合數,所以質數P只可表示成6n+1或6n-1的形式。#ed_op#/P#ed_cl##ed_op#P#ed_cl#2.找出所有的質數P使得P+3亦為質數#ed_op#/P#ed_cl##ed_op#P#ed_cl#P=2,因質數除2外旨為奇數,奇+奇=偶。#ed_op#/P#ed_cl##ed_op#P#ed_cl#3.證明:是否有無限多個質數P使得P+2亦為質數,若非無限多個,請找出P的最大值#ed_op#/P#ed_cl##ed_op#P#ed_cl#這是孿生質數的問題,as far as i know,there is no proof~~~~#ed_op#/P#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#