+ / -檢視主題
[數學]求第三高的範圍
由 picar 於 星期六 十二月 09, 2006 6:50 pm
#ed_op#DIV#ed_cl#解題速度真快感謝您#ed_op#/DIV#ed_cl#
由 n111111111 於 星期六 十二月 09, 2006 6:30 pm
#ed_op#DIV#ed_cl##ed_op#DIV#ed_cl#由三角形面積 1/2 * a * ha = S 所以 a = 2S/ha 同理 b = 2S/hb, c=2S/hc#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#且三角形三邊長 a + b > c, b+c>a, a+c>b 代入求解得#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#3 < h < 6 但三邊相異，所以 h 不等於 4#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#所以 3< h < 6 但 h 不等於 4#ed_op#/DIV#ed_cl##ed_op#/DIV#ed_cl#
[數學]求第三高的範圍
由 picar 於 星期六 十二月 09, 2006 6:12 pm
#ed_op#P class=MsoNormal style="MARGIN: 0cm 0cm 0pt 24pt; LAYOUT-GRID-MODE: char; TEXT-INDENT: -24pt; LINE-HEIGHT: 25pt; mso-list: l0 level1 lfo1; tab-stops: list 24.0pt"#ed_cl##ed_op#SPAN style="FONT-FAMILY: 標楷體; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"#ed_cl#三邊長均相異的#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 標楷體"#ed_cl#△#ed_op#/SPAN#ed_cl##ed_op#I style="mso-bidi-font-style: normal"#ed_cl##ed_op#SPAN lang=EN-US style="mso-fareast-font-family: 標楷體"#ed_cl#ABC#ed_op#/SPAN#ed_cl##ed_op#/I#ed_cl##ed_op#SPAN style="FONT-FAMILY: 標楷體; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"#ed_cl#，已知其中兩個高的長分別為#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="mso-fareast-font-family: 標楷體"#ed_cl#4#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 標楷體; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"#ed_cl#、#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="mso-fareast-font-family: 標楷體"#ed_cl#12#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 標楷體; mso-ascii-font-family: 'Times New Roman'"#ed_cl#，則第三高的長#ed_op#/SPAN#ed_cl##ed_op#I style="mso-bidi-font-style: normal"#ed_cl##ed_op#SPAN lang=EN-US style="mso-fareast-font-family: 標楷體; mso-hansi-font-family: 標楷體"#ed_cl#h#ed_op#/SPAN#ed_cl##ed_op#/I#ed_cl##ed_op#SPAN style="FONT-FAMILY: 標楷體; mso-ascii-font-family: 'Times New Roman'"#ed_cl#之範圍為多少？#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="mso-fareast-font-family: 標楷體"#ed_cl##ed_op#?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /#ed_cl##ed_op#o:p#ed_cl##ed_op#/o:p#ed_cl##ed_op#/SPAN#ed_cl##ed_op#/P#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#