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由 **宇智波鼬** 於星期六十一月 04, 2006 2:42 pm

延長CF和EG相交於X
因為CFA=XFG=DFG XGF=EGB=DGF FG=FG
所以三角形XFG=三角形DFG 所以X也在圓上.
角CFA+角EGB=1/2(弧AX+弧EB+弧CA+弧XB)=1/2(180+60+20)=130
所以角FXG=FDG=180-130=50度

由 **tangpakchiu** 於星期六十一月 04, 2006 1:17 pm

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