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由 jackhoung 於 星期五 七月 28, 2006 10:21 am
#ed_op#DIV#ed_cl#同一圓或等圓中#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#等弦對等弦心距對等弧#ed_op#/DIV#ed_cl#
[問題]我有問題
由 tangpakchiu 於 星期五 七月 28, 2006 9:43 am
#ed_op#DIV#ed_cl#想問問jackhoung，為什麼#ed_op#DIV#ed_cl#只要O1E=O2F，那麼AC=BD???#ed_op#/DIV#ed_cl##ed_op#/DIV#ed_cl#
由 jackhoung 於 星期四 七月 27, 2006 7:36 pm
#ed_op#DIV#ed_cl#作O1E垂直AC於E#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#DIV#ed_cl#作O2F垂直BD於F#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#則ΔO1PE全等於ΔO2PF#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#O1E=O2F#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#AC=BD#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#弧AC=弧BD#ed_op#/DIV#ed_cl##ed_op#/DIV#ed_cl#
[問題]幾何題26
由 tangpakchiu 於 星期四 七月 27, 2006 6:21 pm
#ed_op#DIV#ed_cl##ed_op#IMG alt="image file name: 2k3881e9c0ec.gif" src="http://yll.loxa.edu.tw/phpBB2/richedit/upload/2k3881e9c0ec.gif" border=0#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#已知☉#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O1#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#與☉#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O2#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#是等圓，並兩圓外離，#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#P#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#是#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O1#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O2#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#的中點，#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#AB#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#是過#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#P#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#的直線交☉#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O1#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#於#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#A#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#和#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#C#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#兩點，交☉#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#O2#ed_op#/SPAN#ed_cl##ed_op#SPAN style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 新細明體"#ed_cl#於#ed_op#/SPAN#ed_cl##ed_op#SPAN lang=EN-US style="FONT-FAMILY: 新細明體; mso-font-kerning: 0pt; mso-bidi-font-family: 新細明體"#ed_cl#B和D兩點，求證arcAC=arcBD。#ed_op#/SPAN#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#/DIV#ed_cl#