YLL討論網

tangpakchiu 寫到:#ed_op#DIV#ed_cl#是(2#ed_op#SUP#ed_cl#x+y#ed_op#/SUP#ed_cl#)+(3#ed_op#SUP#ed_cl#2x-y#ed_op#/SUP#ed_cl#)=1,x=?,y=?這個樣子,是有解的。#ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#是有解的#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#但只有一個式子#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#會有無窮多解#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#若x+y=a#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2x-y=b#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#原式可變為#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2#ed_op#SUP#ed_cl#a#ed_op#/SUP#ed_cl#+3#ed_op#SUP#ed_cl#b#ed_op#/SUP#ed_cl#=1#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#當a=0,b=-#ed_op#SPAN style="FONT-SIZE: 12pt; FONT-FAMILY: 新細明體; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-TW; mso-bidi-language: AR-SA"#ed_cl#∞#ed_op#/SPAN#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl##ed_op#SPAN style="FONT-SIZE: 12pt; FONT-FAMILY: 新細明體; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-TW; mso-bidi-language: AR-SA"#ed_cl#當b=0,a=-#ed_op#SPAN style="FONT-SIZE: 12pt; FONT-FAMILY: 新細明體; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-TW; mso-bidi-language: AR-SA"#ed_cl#∞#ed_op#/SPAN#ed_cl##ed_op#/SPAN#ed_cl##ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#在(-#ed_op#SPAN style="FONT-SIZE: 12pt; FONT-FAMILY: 新細明體; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-TW; mso-bidi-language: AR-SA"#ed_cl#∞#ed_op#/SPAN#ed_cl#,0)中可以找到無窮對解#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl#是(2#ed_op#SUP#ed_cl#x+y#ed_op#/SUP#ed_cl#)+(3#ed_op#SUP#ed_cl#2x-y#ed_op#/SUP#ed_cl#)=1,x=?,y=?這個樣子,是有解的。#ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl#他的題目是不是#ed_op#DIV#ed_cl#(2#ed_op#SUP#ed_cl#x+y#ed_op#/SUP#ed_cl#)+(3#ed_op#SUP#ed_cl#2x-y#ed_op#/SUP#ed_cl#)=1,x=?,y=?#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#不過這樣看起來好像無解#ed_op#/DIV#ed_cl##ed_op#/DIV#ed_cl#

革命萬歲! 寫到:#ed_op#DIV#ed_cl#(2^x+y)+(3^2x-y)=1,x=?,y=?#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2^x+3^2x=1#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#其實不太多解吧......#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#y可以是任何數!#ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#"y可以是任何數"就是有無窮多解#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl#(2^x+y)+(3^2x-y)=1,x=?,y=?#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#2^x+3^2x=1#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#其實不太多解吧......#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#y可以是任何數!#ed_op#/DIV#ed_cl#

兩個變量一個方式
沒有其他條件應該有很多很多解

#ed_op#DIV#ed_cl#據老師所講，總共有3個答案，但他不告訴我們解法，要我們上網找。#ed_op#/DIV#ed_cl#

#ed_op#DIV#ed_cl#(2^x+y)+(3^2x-y)=1,x=?,y=?#ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl# #ed_op#/DIV#ed_cl##ed_op#DIV#ed_cl#這題我覺得好難ar,幫幫忙吧!!!#ed_op#/DIV#ed_cl#