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由 chanjunhong 於 星期四 十一月 03, 2005 4:41 pm
x is continuous and differentiable function
then max. and min. values p have the property:
there are two cases, first sin(x)=p with a constraint condition which
and when it happened, the value of function is max. Second,
the extreme value happened at cos(x)=0 ie x=2npi or (2n+1)pi
ie sin(x)=1 or -1 so, q=17/2, p=3/4 or -3/4
the first condition the max. value is
the min. value is :
solve the solution :
由 chanjunhong 於 星期四 十一月 03, 2005 2:13 pm
GFIF 寫到:sorry
砍掉吧
The answer is wrong, why cut off?
(-1,9) max=11 min 7
(2,6) max=10 min=2
由 GFIF 於 星期四 十一月 03, 2005 12:57 pm
sorry
砍掉吧
砍掉吧
由 galaxylee 於 星期四 十一月 03, 2005 2:27 am
[數學]求p、q的值
由 GFIF 於 星期四 十一月 03, 2005 12:40 am
設，且此函數最大值為10，最小值為7，求p、q的值